List intersection Returns a list of elements that exist in both lists. Create a set from a and b. Use the built-in set operator & to only keep values contained in both sets, then transform the set back into a list. def intersection(a, b): _a, _b = set(a), set(b) return list(_a & _b) intersection([1, 2, 3], [4, 3, 2]) # [2, 3]